What is the value of 0-6tan(30)+1/2*9.8*(6/(7.5*cos(30)))^2 ?

The value of 0-6tan(30)+1/2*9.8*(6/(7.5*cos(30)))^2 is 1568/375-2sqrt(3)

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0-6tan(30)+1/29.8(6/(7.5*cos(30)))^2

0 - 6 tan (3 0^{\circ}) + \frac{1}{2} \cdot 9.8 \cdot (\frac{6}{7.5 \cdot cos ( 3 0 ^{\circ} )})^{2}

\frac{1568}{375} - 23

Solution steps

0 - 6 tan (3 0^{\circ}) + \frac{1}{2} \cdot 9.8 (\frac{6}{7.5 cos ( 3 0 ^{\circ} )})^{2}

= 0 - 6 tan (3 0^{\circ}) + \frac{1}{2} \cdot \frac{49}{5} (\frac{6}{\frac{15}{2} cos ( 3 0 ^{\circ} )})^{2}

Use the following trivial identity:

tan (3 0^{\circ}) = \frac{3}{3}

Use the following trivial identity:

cos (3 0^{\circ}) = \frac{3}{2}

= 0 - 6 \cdot \frac{3}{3} + \frac{1}{2} \cdot \frac{49}{5} (\frac{6}{\frac{15}{2} \cdot \frac{3}{2}})^{2}

Simplify

0 - 6 \cdot \frac{3}{3} + \frac{1}{2} \cdot \frac{49}{5} (\frac{6}{\frac{15}{2} \cdot \frac{3}{2}})^{2} : \frac{1568}{375} - 23

= \frac{1568}{375} - 23

sec (4 2^{\circ})

\frac{\frac{π}{3} cos ( \frac{π}{3} ) - sin ( \frac{π}{3} )}{( \frac{π}{3} ) ^{2}}

arccos (\frac{5}{2})

0.23 \cdot cos (62. 2^{\circ})

arctan (\frac{22}{21})

What is the value of 0-6tan(30)+1/2*9.8*(6/(7.5*cos(30)))^2 ?
The value of 0-6tan(30)+1/2*9.8*(6/(7.5*cos(30)))^2 is 1568/375-2sqrt(3)