What is the value of 1/(cos^2(pi/6)) ?

The value of 1/(cos^2(pi/6)) is 4/3

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1/(cos^2(pi/6))

\frac{1}{cos ^{2} ( \frac{π}{6} )}

\frac{4}{3}

Decimal Notation

1.33333 \dots

Solution steps

\frac{1}{cos ^{2} ( \frac{π}{6} )}

Use the following trivial identity:

cos (\frac{π}{6}) = \frac{3}{2}

cos (\frac{π}{6})

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{3}{2}

= \frac{1}{( \frac{3}{2} ) ^{2}}

Simplify

\frac{1}{( \frac{3}{2} ) ^{2}} : \frac{4}{3}

\frac{1}{( \frac{3}{2} ) ^{2}}

(\frac{3}{2})^{2} = \frac{3}{2 ^{2}}

(\frac{3}{2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 3 ) ^{2}}{2 ^{2}}

(3)^{2} : 3

Apply radical rule:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 3

= \frac{3}{2 ^{2}}

= \frac{1}{\frac{3}{2 ^{2}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{2 ^{2}}{3}

2^{2} = 4

= \frac{4}{3}

= \frac{4}{3}

\frac{16.58}{2} \cdot sin (4^{\circ})

sin (0 + π)

0.15 cos (2 π \cdot 0.25)

24 sin (4 5^{\circ})

10 \cdot 6 \cdot cos (12 0^{\circ})