What is the value of 1+tan^2(60)-sec^2(60) ?

The value of 1+tan^2(60)-sec^2(60) is 0

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1+tan^2(60)-sec^2(60)

1 + tan^{2} (6 0^{\circ}) - sec^{2} (6 0^{\circ})

0

Solution steps

1 + tan^{2} (6 0^{\circ}) - sec^{2} (6 0^{\circ})

Use the following trivial identity:

tan (6 0^{\circ}) = 3

Use the following trivial identity:

sec (6 0^{\circ}) = 2

= 1 + (3)^{2} - 2^{2}

Simplify

1 + (3)^{2} - 2^{2} : 0

= 0

cos (\frac{π}{4}) - \frac{π}{4}

(\frac{3}{2}) (\frac{9.8}{0.4}) (1 - sin (6 0^{\circ}) + cos (6 0^{\circ}))

cos (0.68)

cos (15 0^{\circ}) - sin (24 0^{\circ}) + tan (30 0^{\circ})

arctan (\frac{- \frac{3}{2}}{\frac{1}{2}})

What is the value of 1+tan^2(60)-sec^2(60) ?
The value of 1+tan^2(60)-sec^2(60) is 0