What is the value of -2sin(135) ?

The value of -2sin(135) is -sqrt(2)

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-2sin(135)

- 2 sin (13 5^{\circ})

- 2

Decimal Notation

- 1.41421 \dots

Solution steps

- 2 sin (13 5^{\circ})

Use the following trivial identity:

sin (13 5^{\circ}) = \frac{2}{2}

sin (13 5^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{2}{2}

= - 2 \cdot \frac{2}{2}

Simplify

- 2 \cdot \frac{2}{2} : - 2

- 2 \cdot \frac{2}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{2 \cdot 2}{2}

Cancel the common factor:

2

= - 2

= - 2

\frac{arccos ( \frac{1}{2} )}{3}

128 + 127.5 sin (\frac{2 π}{16} \cdot 4)

arccot (\frac{8}{15})

4 \cdot sin (\frac{π}{2})

10 sin (π^{0.29})