What is the value of cos(arctan(6/5)) ?

The value of cos(arctan(6/5)) is (5sqrt(61))/(61)

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cos(arctan(6/5))

cos (arctan (\frac{6}{5}))

\frac{5 61}{61}

Solution steps

cos (arctan (\frac{6}{5}))

Rewrite using trig identities:

cos (arctan (\frac{6}{5})) = \frac{1 + ( \frac{6}{5} ) ^{2}}{1 + ( \frac{6}{5} ) ^{2}}

= \frac{1 + ( \frac{6}{5} ) ^{2}}{1 + ( \frac{6}{5} ) ^{2}}

Simplify

= \frac{5 61}{61}

arctan (\frac{0.0258}{0.004})

arccos (\frac{1 7 ^{2} - 9.7 5 ^{2} - 2 2 ^{2}}{- 2 \cdot 9.75 \cdot 22})

2 + 2 cos (\frac{3 π}{2})

\frac{3}{4} (sin (\frac{15 π}{2})) + 2

20 sin (15 0^{\circ})

What is the value of cos(arctan(6/5)) ?
The value of cos(arctan(6/5)) is (5sqrt(61))/(61)