What is the general solution for 6sin^2(x)-5sin(x)=0 ?

The general solution for 6sin^2(x)-5sin(x)=0 is x=0.98511…+2pin,x=pi-0.98511…+2pin,x=2pin,x=pi+2pin

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6sin^2(x)-5sin(x)=0

Solution

6 sin^{2} (x) - 5 sin (x) = 0

Solution

x = 0.98511 \dots + 2 πn, x = π - 0.98511 \dots + 2 πn, x = 2 πn, x = π + 2 πn

Degrees

x = 56.44269 \dots^{\circ} + 36 0^{\circ} n, x = 123.55730 \dots^{\circ} + 36 0^{\circ} n, x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

6 sin^{2} (x) - 5 sin (x) = 0

Solve by substitution

6 sin^{2} (x) - 5 sin (x) = 0

Let:

sin (x) = u

6 u^{2} - 5 u = 0

6 u^{2} - 5 u = 0 : u = \frac{5}{6}, u = 0

6 u^{2} - 5 u = 0

Solve with the quadratic formula

6 u^{2} - 5 u = 0

Quadratic Equation Formula:

For

a = 6, b = - 5, c = 0

u_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

u_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

(- 5)^{2} - 4 \cdot 6 \cdot 0 = 5

(- 5)^{2} - 4 \cdot 6 \cdot 0

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 5)^{2} = 5^{2}

= 5^{2} - 4 \cdot 6 \cdot 0

Apply rule

0 \cdot a = 0

= 5^{2} - 0

5^{2} - 0 = 5^{2}

= 5^{2}

Apply radical rule:

assuming

a \geq 0

= 5

u_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 6}

Separate the solutions

u_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 6}, u_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 6}

u = \frac{- ( - 5 ) + 5}{2 \cdot 6} : \frac{5}{6}

\frac{- ( - 5 ) + 5}{2 \cdot 6}

Apply rule

- (- a) = a

= \frac{5 + 5}{2 \cdot 6}

Add the numbers:

5 + 5 = 10

= \frac{10}{2 \cdot 6}

Multiply the numbers:

2 \cdot 6 = 12

= \frac{10}{12}

Cancel the common factor:

2

= \frac{5}{6}

u = \frac{- ( - 5 ) - 5}{2 \cdot 6} : 0

\frac{- ( - 5 ) - 5}{2 \cdot 6}

Apply rule

- (- a) = a

= \frac{5 - 5}{2 \cdot 6}

Subtract the numbers:

5 - 5 = 0

= \frac{0}{2 \cdot 6}

Multiply the numbers:

2 \cdot 6 = 12

= \frac{0}{12}

Apply rule

\frac{0}{a} = 0, a \neq = 0

= 0

The solutions to the quadratic equation are:

u = \frac{5}{6}, u = 0

Substitute back

u = sin (x)

sin (x) = \frac{5}{6}, sin (x) = 0

sin (x) = \frac{5}{6}, sin (x) = 0

sin (x) = \frac{5}{6} : x = arcsin (\frac{5}{6}) + 2 πn, x = π - arcsin (\frac{5}{6}) + 2 πn

sin (x) = \frac{5}{6}

Apply trig inverse properties

sin (x) = \frac{5}{6}

General solutions for

sin (x) = \frac{5}{6}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

x = arcsin (\frac{5}{6}) + 2 πn, x = π - arcsin (\frac{5}{6}) + 2 πn

x = arcsin (\frac{5}{6}) + 2 πn, x = π - arcsin (\frac{5}{6}) + 2 πn

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 0

General solutions for

sin (x) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

Combine all the solutions

x = arcsin (\frac{5}{6}) + 2 πn, x = π - arcsin (\frac{5}{6}) + 2 πn, x = 2 πn, x = π + 2 πn

Show solutions in decimal form

x = 0.98511 \dots + 2 πn, x = π - 0.98511 \dots + 2 πn, x = 2 πn, x = π + 2 πn

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Frequently Asked Questions (FAQ)

What is the general solution for 6sin^2(x)-5sin(x)=0 ?
The general solution for 6sin^2(x)-5sin(x)=0 is x=0.98511…+2pin,x=pi-0.98511…+2pin,x=2pin,x=pi+2pin