What is the general solution for -sqrt(2)sin(x)-1=0 ?

The general solution for -sqrt(2)sin(x)-1=0 is x=(5pi)/4+2pin,x=(7pi)/4+2pin

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-sqrt(2)sin(x)-1=0

- 2 sin (x) - 1 = 0

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Solution steps

- 2 sin (x) - 1 = 0

Move

1

to the right side

- 2 sin (x) = 1

Divide both sides by

- 2

sin (x) = - \frac{2}{2}

General solutions for

sin (x) = - \frac{2}{2}

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

- 3 = cot^{2} (θ) + 3 csc (θ)

arccos (e^{- x}) = \frac{π}{3}

cos (θ) = - \frac{11}{170}

2 cos^{2} (θ) - 7 cos (θ) + 3 = 0, 0 \leq θ \leq 2 π

4 sin (x) cos (x) + 2 sin (x) - 2 cos (x) = 1

What is the general solution for -sqrt(2)sin(x)-1=0 ?
The general solution for -sqrt(2)sin(x)-1=0 is x=(5pi)/4+2pin,x=(7pi)/4+2pin