What is the general solution for picos(θ)=-pi/2 ?

The general solution for picos(θ)=-pi/2 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

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picos(θ)=-pi/2

π cos (θ) = - \frac{π}{2}

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solution steps

π cos (θ) = - \frac{π}{2}

Divide both sides by

π

cos (θ) = - \frac{1}{2}

General solutions for

cos (θ) = - \frac{1}{2}

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

x, y = 1 + sin (\frac{π x}{4})

sin (x) + sin (\frac{x}{2}) = 0

sin^{3} (x) + sin (x) = 2 cos^{2} (x)

4 sin^{2} (x) + 2 cos^{2} (x) = 3

cos^{2} (θ) - 3 sin (2 θ) + sin^{2} (θ) + 2 sin^{2} (2 θ) = 0

What is the general solution for picos(θ)=-pi/2 ?
The general solution for picos(θ)=-pi/2 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin