What is the general solution for 3cos^2(x)+6cos(x)=-3 ?

The general solution for 3cos^2(x)+6cos(x)=-3 is x=pi+2pin

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3cos^2(x)+6cos(x)=-3

3 cos^{2} (x) + 6 cos (x) = - 3

x = π + 2 πn

Solution steps

3 cos^{2} (x) + 6 cos (x) = - 3

Solve by substitution

cos (x) = - 1

cos (x) = - 1 : x = π + 2 πn

Combine all the solutions

x = π + 2 πn

sin (2 x + 4) = cos (4 6^{\circ})

52 cos (x) - 10 sin (x) cos (x) = 0

tan^{2} (x) - cos^{2} (x) = sin^{2} (x)

cos^{2} (x) = \frac{( 8 k - 7 )}{7}

2 cos^{2} (x) - 7 cos (x) = - 3

What is the general solution for 3cos^2(x)+6cos(x)=-3 ?
The general solution for 3cos^2(x)+6cos(x)=-3 is x=pi+2pin