What is the general solution for 2-5cos(x+1)=4 ?

The general solution for 2-5cos(x+1)=4 is x=1.98231…+2pin-1,x=-1.98231…+2pin-1

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2-5cos(x+1)=4

2 - 5 cos (x + 1) = 4

x = 1.98231 \dots + 2 πn - 1, x = - 1.98231 \dots + 2 πn - 1

Solution steps

2 - 5 cos (x + 1) = 4

Move

2

to the right side

- 5 cos (x + 1) = 2

Divide both sides by

- 5

cos (x + 1) = - \frac{2}{5}

Apply trig inverse properties

x + 1 = arccos (- \frac{2}{5}) + 2 πn, x + 1 = - arccos (- \frac{2}{5}) + 2 πn

Solve

x + 1 = arccos (- \frac{2}{5}) + 2 πn : x = arccos (- \frac{2}{5}) + 2 πn - 1

Solve

x + 1 = - arccos (- \frac{2}{5}) + 2 πn : x = - arccos (- \frac{2}{5}) + 2 πn - 1

x = arccos (- \frac{2}{5}) + 2 πn - 1, x = - arccos (- \frac{2}{5}) + 2 πn - 1

Show solutions in decimal form

x = 1.98231 \dots + 2 πn - 1, x = - 1.98231 \dots + 2 πn - 1

2 (tan (θ) + 3) = 5 + tan (θ)

sin^{2} (x) = \frac{( 9 m - 8 )}{2}

\frac{5}{2} cos (2 x) - \frac{1}{2} = 3 sin (x)

cos (π + x) = \frac{1}{2}

(tan (x) - 4) (16 sin^{2} (x) - 1) = 0

What is the general solution for 2-5cos(x+1)=4 ?
The general solution for 2-5cos(x+1)=4 is x=1.98231…+2pin-1,x=-1.98231…+2pin-1