What is the general solution for sin(x-1)=0 ?

The general solution for sin(x-1)=0 is x=2pin+1,x=pi+2pin+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(x-1)=0

sin (x - 1) = 0

x = 2 πn + 1, x = π + 2 πn + 1

Degrees

x = 57.29577 \dots^{\circ} + 36 0^{\circ} n, x = 237.29577 \dots^{\circ} + 36 0^{\circ} n

Solution steps

sin (x - 1) = 0

General solutions for

sin (x - 1) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x - 1 = 0 + 2 πn, x - 1 = π + 2 πn

x - 1 = 0 + 2 πn, x - 1 = π + 2 πn

Solve

x - 1 = 0 + 2 πn : x = 2 πn + 1

x - 1 = 0 + 2 πn

0 + 2 πn = 2 πn

x - 1 = 2 πn

Move

1

to the right side

x - 1 = 2 πn

Add

1

to both sides

x - 1 + 1 = 2 πn + 1

Simplify

x = 2 πn + 1

x = 2 πn + 1

Solve

x - 1 = π + 2 πn : x = π + 2 πn + 1

x - 1 = π + 2 πn

Move

1

to the right side

x - 1 = π + 2 πn

Add

1

to both sides

x - 1 + 1 = π + 2 πn + 1

Simplify

x = π + 2 πn + 1

x = π + 2 πn + 1

x = 2 πn + 1, x = π + 2 πn + 1

x, arcsin (x) + arcsin (y) = \frac{2 π}{3}

cot (θ) = 2 cos (θ)

csc (θ) = - 0.5

cot (2 t + 5) = tan (3 t - 15)

cos (2 x) = \frac{( 8 k - 9 )}{2}

What is the general solution for sin(x-1)=0 ?
The general solution for sin(x-1)=0 is x=2pin+1,x=pi+2pin+1