What is the general solution for tan(x)=-1,-pi<= x<= pi ?

The general solution for tan(x)=-1,-pi<= x<= pi is x=(3pi)/4 ,x=-pi/4

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tan(x)=-1,-pi<= x<= pi

tan (x) = - 1, - π \leq x \leq π

x = \frac{3 π}{4}, x = - \frac{π}{4}

Degrees

x = 13 5^{\circ}, x = - 4 5^{\circ}

Solution steps

tan (x) = - 1, - π \leq x \leq π

General solutions for

tan (x) = - 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{3 π}{4} + πn

x = \frac{3 π}{4} + πn

Solutions for the range

- π \leq x \leq π

x = \frac{3 π}{4}, x = - \frac{π}{4}

cos^{2} (x) - sin^{2} (x) - 1 = 0

3 (2 + cos (x)) = 5

tan (x) = \frac{5}{8.66}

3 tan (x) - 4 = tan (x) - 2

0 = - sin (x) - 1

What is the general solution for tan(x)=-1,-pi<= x<= pi ?
The general solution for tan(x)=-1,-pi<= x<= pi is x=(3pi)/4 ,x=-pi/4