What is the general solution for solvefor x,cos^2(x)=2+2sin(x) ?

The general solution for solvefor x,cos^2(x)=2+2sin(x) is x=(3pi)/2+2pin

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solvefor x,cos^2(x)=2+2sin(x)

solve for

x, cos^{2} (x) = 2 + 2 sin (x)

x = \frac{3 π}{2} + 2 πn

Solution steps

cos^{2} (x) = 2 + 2 sin (x)

Subtract

2 + 2 sin (x)

from both sides

cos^{2} (x) - 2 - 2 sin (x) = 0

Rewrite using trig identities

- 1 - sin^{2} (x) - 2 sin (x) = 0

Solve by substitution

sin (x) = - 1

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{3 π}{2} + 2 πn

1 - sin (x) = 1

- sin (2 x) = \frac{cos ( 2 x )}{3}

sin (x) + cos (x) \cdot cot (x) = 2

4 sin (θ) = 3 sec (θ)

x, (d^{2} - 3 d + 2) y = cos (e^{- x})

What is the general solution for solvefor x,cos^2(x)=2+2sin(x) ?
The general solution for solvefor x,cos^2(x)=2+2sin(x) is x=(3pi)/2+2pin