What is the general solution for 1+4sin(θ)=0 ?

The general solution for 1+4sin(θ)=0 is θ=-0.25268…+2pin,θ=pi+0.25268…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1+4sin(θ)=0

1 + 4 sin (θ) = 0

θ = - 0.25268 \dots + 2 πn, θ = π + 0.25268 \dots + 2 πn

Solution steps

1 + 4 sin (θ) = 0

Move

1

to the right side

4 sin (θ) = - 1

Divide both sides by

4

sin (θ) = - \frac{1}{4}

Apply trig inverse properties

θ = arcsin (- \frac{1}{4}) + 2 πn, θ = π + arcsin (\frac{1}{4}) + 2 πn

Show solutions in decimal form

θ = - 0.25268 \dots + 2 πn, θ = π + 0.25268 \dots + 2 πn

2 sin (x) + cos (x) = - 2

sin (x) - sin (2 x) = 0, x \leq 2 π, 0

- sin (x) - 2 cot (x) + 5 csc (x) = 0

3 cos^{2} (x) = sin^{2} (x) + 2

cos (x) = \frac{π}{3}

What is the general solution for 1+4sin(θ)=0 ?
The general solution for 1+4sin(θ)=0 is θ=-0.25268…+2pin,θ=pi+0.25268…+2pin