What is the general solution for sin^2(4x)=1 ?

The general solution for sin^2(4x)=1 is x= pi/8+(pin)/2 ,x=(3pi)/8+(pin)/2

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sin^2(4x)=1

sin^{2} (4 x) = 1

x = \frac{π}{8} + \frac{πn}{2}, x = \frac{3 π}{8} + \frac{πn}{2}

Solution steps

sin^{2} (4 x) = 1

Solve by substitution

sin (4 x) = 1, sin (4 x) = - 1

sin (4 x) = 1 : x = \frac{π}{8} + \frac{πn}{2}

sin (4 x) = - 1 : x = \frac{3 π}{8} + \frac{πn}{2}

Combine all the solutions

x = \frac{π}{8} + \frac{πn}{2}, x = \frac{3 π}{8} + \frac{πn}{2}

sinh (x) = \frac{2}{3}

cos (α_{2}) = \frac{1}{14}, 0 \leq α_{2} \leq 2 π

sin (2 x + 60) = \frac{1}{2}

tan^{3} (x) - 3 tan (x) = 0

2 cos (x) = 2 cos (2 x)

What is the general solution for sin^2(4x)=1 ?
The general solution for sin^2(4x)=1 is x= pi/8+(pin)/2 ,x=(3pi)/8+(pin)/2