What is the general solution for sin(pi+θ)=sin(θ) ?

The general solution for sin(pi+θ)=sin(θ) is θ=2pin,θ=pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(pi+θ)=sin(θ)

sin (π + θ) = sin (θ)

θ = 2 πn, θ = π + 2 πn

Solution steps

sin (π + θ) = sin (θ)

Rewrite using trig identities

- sin (θ) = sin (θ)

Subtract

sin (θ)

from both sides

- 2 sin (θ) = 0

Divide both sides by

- 2

sin (θ) = 0

General solutions for

sin (θ) = 0

θ = 0 + 2 πn, θ = π + 2 πn

Solve

θ = 0 + 2 πn : θ = 2 πn

θ = 2 πn, θ = π + 2 πn

0 = 2 cos (x) + sin (x)

2 sin^{3} (x) - sin^{2} (x) - sin (x) = 0

tan (t) + sec (t) = 1

sin (5 x - 10) = cos (x - 8)

sin^{2} (x) + 5 sin (x) = 3

What is the general solution for sin(pi+θ)=sin(θ) ?
The general solution for sin(pi+θ)=sin(θ) is θ=2pin,θ=pi+2pin