en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(3x)=0,0<= x<2pi

Solution

sin (3 x) = 0, 0 \leq x < 2 π

Solution

x = 0, x = \frac{π}{3}, x = \frac{2 π}{3}, x = π, x = \frac{4 π}{3}, x = \frac{5 π}{3}

+1

Solution steps

sin (3 x) = 0, 0 \leq x < 2 π

General solutions for

sin (3 x) = 0

3 x = 0 + 2 πn, 3 x = π + 2 πn

Solve

3 x = 0 + 2 πn : x = \frac{2 πn}{3}

Solve

3 x = π + 2 πn : x = \frac{π}{3} + \frac{2 πn}{3}

x = \frac{2 πn}{3}, x = \frac{π}{3} + \frac{2 πn}{3}

Solutions for the range

0 \leq x < 2 π

x = 0, x = \frac{π}{3}, x = \frac{2 π}{3}, x = π, x = \frac{4 π}{3}, x = \frac{5 π}{3}

Popular Examples

2cos^2(x)=sqrt(3)cos(x)

2 cos^{2} (x) = 3 cos (x)

sin(θ)=-1/5 ,pi<θ<(3pi)/2 ,cos(θ)

sin (θ) = - \frac{1}{5}, π < θ < \frac{3 π}{2}, cos (θ)

sqrt(3)cot(θ)-1=0,0<= θ<= 2pi

3 cot (θ) - 1 = 0, 0 \leq θ \leq 2 π

(sin(x))/(37)=(sin(30))/(30)

\frac{sin ( x )}{37} = \frac{sin ( 3 0 ^{\circ} )}{30}

1-cos(x)=cos(x)

1 - cos (x) = cos (x)

Frequently Asked Questions (FAQ)

What is the general solution for sin(3x)=0,0<= x<2pi ?
The general solution for sin(3x)=0,0<= x<2pi is x=0,x= pi/3 ,x=(2pi)/3 ,x=pi,x=(4pi)/3 ,x=(5pi)/3