What is the general solution for 2cos^2(x)+15sin(x)-15=0 ?

The general solution for 2cos^2(x)+15sin(x)-15=0 is x= pi/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cos^2(x)+15sin(x)-15=0

2 cos^{2} (x) + 15 sin (x) - 15 = 0

x = \frac{π}{2} + 2 πn

Solution steps

2 cos^{2} (x) + 15 sin (x) - 15 = 0

Rewrite using trig identities

- 13 + 15 sin (x) - 2 sin^{2} (x) = 0

Solve by substitution

sin (x) = 1, sin (x) = \frac{13}{2}

sin (x) = 1 : x = \frac{π}{2} + 2 πn

sin (x) = \frac{13}{2} :

No Solution

Combine all the solutions

x = \frac{π}{2} + 2 πn

cos (2 x) = sin (x), - 2 π \leq x \leq 2 π

5 sec^{2} (θ) sin (θ) - cos (θ) = 0

cos (x) = \frac{8}{11}

4 sec (θ) - 3 = 3 + 7 sec (θ)

\frac{1}{15} = cos (x)

What is the general solution for 2cos^2(x)+15sin(x)-15=0 ?
The general solution for 2cos^2(x)+15sin(x)-15=0 is x= pi/2+2pin