What is the general solution for 4=2+2sin(θ) ?

The general solution for 4=2+2sin(θ) is θ= pi/2+2pin

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4=2+2sin(θ)

4 = 2 + 2 sin (θ)

θ = \frac{π}{2} + 2 πn

Solution steps

4 = 2 + 2 sin (θ)

Switch sides

2 + 2 sin (θ) = 4

Move

2

to the right side

2 sin (θ) = 2

Divide both sides by

2

sin (θ) = 1

General solutions for

sin (θ) = 1

θ = \frac{π}{2} + 2 πn

2 sin^{2} (x) - 3 sin (x) - 1 = 0

2 sin (6 x) - 1 = 0

sin^{2} (x) = \frac{( 6 m - 5 )}{5}

sin^{2} (θ) - sin (θ) - 6 = 0

cos (2 θ) - 3 cos (θ) + 2 = 0

What is the general solution for 4=2+2sin(θ) ?
The general solution for 4=2+2sin(θ) is θ= pi/2+2pin