What is the general solution for -4sin(θ)=4(sin(θ)-1) ?

The general solution for -4sin(θ)=4(sin(θ)-1) is θ= pi/6+2pin,θ=(5pi)/6+2pin

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-4sin(θ)=4(sin(θ)-1)

- 4 sin (θ) = 4 (sin (θ) - 1)

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

Solution steps

- 4 sin (θ) = 4 (sin (θ) - 1)

Solve by substitution

sin (θ) = \frac{1}{2}

sin (θ) = \frac{1}{2} : θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

Combine all the solutions

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

4 + 2 cos (θ) = 0

9.81 sin (θ) - 5.88 cos (θ) = 2.77

cos (θ) = π

2 (- sin (x) + cos (2 x)) = 0

sin (x) - cos (x) = 1, 0 \leq x \leq 2 π

What is the general solution for -4sin(θ)=4(sin(θ)-1) ?
The general solution for -4sin(θ)=4(sin(θ)-1) is θ= pi/6+2pin,θ=(5pi)/6+2pin