What is the general solution for 2+2cos(θ)= 2/(1+cos(θ)) ?

The general solution for 2+2cos(θ)= 2/(1+cos(θ)) is θ= pi/2+2pin,θ=(3pi)/2+2pin

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2+2cos(θ)= 2/(1+cos(θ))

2 + 2 cos (θ) = \frac{2}{1 + cos ( θ )}

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

2 + 2 cos (θ) = \frac{2}{1 + cos ( θ )}

Solve by substitution

cos (θ) = 0, cos (θ) = - 2

cos (θ) = 0 : θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

cos (θ) = - 2 :

No Solution

Combine all the solutions

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

14 sin (2 x) + 7 = 0

tan (3 x) + sec (3 x) = 2

cos^{2} (x) + 4 cos (x) - 2 = 0

sin (θ) = \frac{- 2}{3}

sec^{2} (θ) + csc^{2} (θ) = 4

What is the general solution for 2+2cos(θ)= 2/(1+cos(θ)) ?
The general solution for 2+2cos(θ)= 2/(1+cos(θ)) is θ= pi/2+2pin,θ=(3pi)/2+2pin