What is the general solution for 2cos^2(x)=2 ?

The general solution for 2cos^2(x)=2 is x=2pin,x=pi+2pin

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2cos^2(x)=2

2 cos^{2} (x) = 2

x = 2 πn, x = π + 2 πn

Solution steps

2 cos^{2} (x) = 2

Solve by substitution

cos (x) = 1, cos (x) = - 1

cos (x) = 1 : x = 2 πn

cos (x) = - 1 : x = π + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn

0 = - 2 sin (t) - 4 cos (2 t)

cos (θ) + sin (θ + \frac{π}{2}) = 1, 0 \leq θ < 2 π

sin^{2} (x) + cos (2 x) = 0

42 cos (x) - 8 sin (x) cos (x) = 0

sin (x) = cos (x + \frac{π}{2})

What is the general solution for 2cos^2(x)=2 ?
The general solution for 2cos^2(x)=2 is x=2pin,x=pi+2pin