What is the general solution for (cos(x)+1)(cos(x)-4)=0 ?

The general solution for (cos(x)+1)(cos(x)-4)=0 is x=pi+2pin

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(cos(x)+1)(cos(x)-4)=0

(cos (x) + 1) (cos (x) - 4) = 0

x = π + 2 πn

Solution steps

(cos (x) + 1) (cos (x) - 4) = 0

Solving each part separately

cos (x) + 1 = 0 or cos (x) - 4 = 0

cos (x) + 1 = 0 : x = π + 2 πn

cos (x) - 4 = 0 :

No Solution

Combine all the solutions

x = π + 2 πn

cos (10 x) = 0

7 - 5 cos (x) = 10

sin^{2} (θ) - 2 = sin (θ)

5 + 4 cos (x) = 0

csc^{2} (x) - csc (x) - 2 = 0, 0 \leq x \leq 2 π

What is the general solution for (cos(x)+1)(cos(x)-4)=0 ?
The general solution for (cos(x)+1)(cos(x)-4)=0 is x=pi+2pin