What is the general solution for 3|sin(5θ)|=0 ?

The general solution for 3|sin(5θ)|=0 is θ=(2pin)/5 ,θ= pi/5+(2pin)/5

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3|sin(5θ)|=0

3 ∣ sin (5 θ) ∣ = 0

θ = \frac{2 πn}{5}, θ = \frac{π}{5} + \frac{2 πn}{5}

Solution steps

3 ∣ sin (5 θ) ∣ = 0

Divide both sides by

3

∣ sin (5 θ) ∣ = 0

Apply absolute rule: If

∣ u ∣ = 0

then

u = 0

sin (5 θ) = 0

General solutions for

sin (5 θ) = 0

5 θ = 0 + 2 πn, 5 θ = π + 2 πn

Solve

5 θ = 0 + 2 πn : θ = \frac{2 πn}{5}

Solve

5 θ = π + 2 πn : θ = \frac{π}{5} + \frac{2 πn}{5}

θ = \frac{2 πn}{5}, θ = \frac{π}{5} + \frac{2 πn}{5}

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4 cos (A) + 3 = 2 cos (A) + 4

sin^{2} (x) - tan (x) = 0

6 sin^{3} (x) + 7 sin^{2} (x) - sin (x) - 2 = 0

What is the general solution for 3|sin(5θ)|=0 ?
The general solution for 3|sin(5θ)|=0 is θ=(2pin)/5 ,θ= pi/5+(2pin)/5