What is the general solution for tan^2(θ)-sec^2(θ)=cos(-θ) ?

The general solution for tan^2(θ)-sec^2(θ)=cos(-θ) is θ=-pi-2pin

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tan^2(θ)-sec^2(θ)=cos(-θ)

tan^{2} (θ) - sec^{2} (θ) = cos (- θ)

θ = - π - 2 πn

Solution steps

tan^{2} (θ) - sec^{2} (θ) = cos (- θ)

Rewrite using trig identities

- 1 = cos (- θ)

Switch sides

cos (- θ) = - 1

General solutions for

cos (- θ) = - 1

- θ = π + 2 πn

Solve

- θ = π + 2 πn : θ = - π - 2 πn

θ = - π - 2 πn

- 2 sin (t) - 4 cos (2 t) = 0

8 sin (2 x) - 43 = 0

cos (3 x) cos (9 x) + sin (3 x) sin (9 x) = 0

cos (2 x) + 5 sin (x) + 2 = 0, 0 \leq x < 2 π

8 - 12 sin^{2} (θ) = 4 cos^{2} (θ)

What is the general solution for tan^2(θ)-sec^2(θ)=cos(-θ) ?
The general solution for tan^2(θ)-sec^2(θ)=cos(-θ) is θ=-pi-2pin