What is the general solution for 8sin(2x)-4sqrt(3)=0 ?

The general solution for 8sin(2x)-4sqrt(3)=0 is x= pi/6+pin,x= pi/3+pin

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8sin(2x)-4sqrt(3)=0

8 sin (2 x) - 43 = 0

x = \frac{π}{6} + πn, x = \frac{π}{3} + πn

Solution steps

8 sin (2 x) - 43 = 0

Move

43

to the right side

8 sin (2 x) = 43

Divide both sides by

8

sin (2 x) = \frac{3}{2}

General solutions for

sin (2 x) = \frac{3}{2}

2 x = \frac{π}{3} + 2 πn, 2 x = \frac{2 π}{3} + 2 πn

Solve

2 x = \frac{π}{3} + 2 πn : x = \frac{π}{6} + πn

Solve

2 x = \frac{2 π}{3} + 2 πn : x = \frac{π}{3} + πn

x = \frac{π}{6} + πn, x = \frac{π}{3} + πn

cos (3 x) cos (9 x) + sin (3 x) sin (9 x) = 0

cos (2 x) + 5 sin (x) + 2 = 0, 0 \leq x < 2 π

8 - 12 sin^{2} (θ) = 4 cos^{2} (θ)

\frac{sin ( 3 4 ^{\circ} )}{12} = \frac{sin ( x )}{15}

3 - 3 cos (θ) = \frac{3}{2} sec (θ)

What is the general solution for 8sin(2x)-4sqrt(3)=0 ?
The general solution for 8sin(2x)-4sqrt(3)=0 is x= pi/6+pin,x= pi/3+pin