What is the general solution for 2cos^2(x)+3cos(x)+1=0,(0,2pi) ?

The general solution for 2cos^2(x)+3cos(x)+1=0,(0,2pi) is x=(2pi)/3 ,x=(4pi)/3 ,x=pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cos^2(x)+3cos(x)+1=0,(0,2pi)

2 cos^{2} (x) + 3 cos (x) + 1 = 0, (0, 2 π)

x = \frac{2 π}{3}, x = \frac{4 π}{3}, x = π

Solution steps

2 cos^{2} (x) + 3 cos (x) + 1 = 0, (0, 2 π)

Solve by substitution

cos (x) = - \frac{1}{2}, cos (x) = - 1

cos (x) = - \frac{1}{2}, (0, 2 π) : x = \frac{2 π}{3}, x = \frac{4 π}{3}

cos (x) = - 1, (0, 2 π) : x = π

Combine all the solutions

x = \frac{2 π}{3}, x = \frac{4 π}{3}, x = π

- 4 cos (θ) = 4 (1 + cos (θ))

sin (2 a) = 1

tan (2 x) - \frac{1}{tan ( x )} = 0

sin (x) + cos (x) + 1 = 0

tan (x) = 15

What is the general solution for 2cos^2(x)+3cos(x)+1=0,(0,2pi) ?
The general solution for 2cos^2(x)+3cos(x)+1=0,(0,2pi) is x=(2pi)/3 ,x=(4pi)/3 ,x=pi