What is the general solution for cos(θ)=sec(θ) ?

The general solution for cos(θ)=sec(θ) is θ=2pin,θ=pi+2pin

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cos(θ)=sec(θ)

cos (θ) = sec (θ)

θ = 2 πn, θ = π + 2 πn

Solution steps

cos (θ) = sec (θ)

Subtract

sec (θ)

from both sides

cos (θ) - sec (θ) = 0

Rewrite using trig identities

\frac{1}{sec ( θ )} - sec (θ) = 0

Solve by substitution

sec (θ) = 1, sec (θ) = - 1

sec (θ) = 1 : θ = 2 πn

sec (θ) = - 1 : θ = π + 2 πn

Combine all the solutions

θ = 2 πn, θ = π + 2 πn

4.45 tan^{2} (θ) - 23 tan (θ) + 16.15 = 0

sin^{2} (x) = \frac{( 3 m - 2 )}{8}

arccos (x) = arcsin (\frac{1}{3}) + arccos (\frac{1}{4})

sin (2 x) = cos (4 0^{\circ})

- 15 sin (x) - 8 cos (x) = 10

What is the general solution for cos(θ)=sec(θ) ?
The general solution for cos(θ)=sec(θ) is θ=2pin,θ=pi+2pin