What is the general solution for 4sin(θ)=-4cos(θ) ?

The general solution for 4sin(θ)=-4cos(θ) is θ=(3pi)/4+pin

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4sin(θ)=-4cos(θ)

4 sin (θ) = - 4 cos (θ)

θ = \frac{3 π}{4} + πn

Solution steps

4 sin (θ) = - 4 cos (θ)

Rewrite using trig identities

4 tan (θ) = - 4

Divide both sides by

4

tan (θ) = - 1

General solutions for

tan (θ) = - 1

θ = \frac{3 π}{4} + πn

- 3 sin (a) - 2 = sin (a) - 2

tan (A) = 1

3 sec^{2} (x) + 2 tan (x) - 23 = 0

sin (x) (1 - 2 cos (x)) = 0

4 cos^{2} (x) + 3 cos (x) = 1

What is the general solution for 4sin(θ)=-4cos(θ) ?
The general solution for 4sin(θ)=-4cos(θ) is θ=(3pi)/4+pin