What is the general solution for cos(θ)=(4sqrt(2))/7 ?

The general solution for cos(θ)=(4sqrt(2))/7 is θ=0.62983…+2pin,θ=2pi-0.62983…+2pin

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cos(θ)=(4sqrt(2))/7

cos (θ) = \frac{4 2}{7}

θ = 0.62983 \dots + 2 πn, θ = 2 π - 0.62983 \dots + 2 πn

Degrees

θ = 36.08714 \dots^{\circ} + 36 0^{\circ} n, θ = 323.91285 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = \frac{4 2}{7}

Apply trig inverse properties

cos (θ) = \frac{4 2}{7}

General solutions for

cos (θ) = \frac{4 2}{7}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{4 2}{7}) + 2 πn, θ = 2 π - arccos (\frac{4 2}{7}) + 2 πn

θ = arccos (\frac{4 2}{7}) + 2 πn, θ = 2 π - arccos (\frac{4 2}{7}) + 2 πn

Show solutions in decimal form

θ = 0.62983 \dots + 2 πn, θ = 2 π - 0.62983 \dots + 2 πn

sec^{2} (θ) + 2 sec (θ) = 8

8 tan (θ) + 9 = 0

1 + tanh^{2} (x) = sech^{2} (x)

cos (x) - sin (x) = \frac{1}{2}

tan (t) = - \frac{12}{5}

What is the general solution for cos(θ)=(4sqrt(2))/7 ?
The general solution for cos(θ)=(4sqrt(2))/7 is θ=0.62983…+2pin,θ=2pi-0.62983…+2pin