What is the general solution for cos(x)=sin(x),0<= x<= 2pi ?

The general solution for cos(x)=sin(x),0<= x<= 2pi is x= pi/4 ,x=(5pi)/4

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cos(x)=sin(x),0<= x<= 2pi

cos (x) = sin (x), 0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}

Solution steps

cos (x) = sin (x), 0 \leq x \leq 2 π

Rewrite using trig identities

tan (x) = 1

General solutions for

tan (x) = 1

x = \frac{π}{4} + πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}

sin (4 (x - \frac{π}{4})) = 0

3 arcsin (2 θ) = 2 π

cos^{3} (x) + cos^{2} (x) - cos (x) - 1 = 0

tan (2 θ) = 1, 0^{\circ} \leq θ \leq 36 0^{\circ}

2 cos (θ) + 2 = 0, 0 \leq θ \leq 2 π

What is the general solution for cos(x)=sin(x),0<= x<= 2pi ?
The general solution for cos(x)=sin(x),0<= x<= 2pi is x= pi/4 ,x=(5pi)/4