What is the general solution for 1-cos(θ)=cos(θ) ?

The general solution for 1-cos(θ)=cos(θ) is θ= pi/3+2pin,θ=(5pi)/3+2pin

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1-cos(θ)=cos(θ)

1 - cos (θ) = cos (θ)

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Solution steps

1 - cos (θ) = cos (θ)

Solve by substitution

cos (θ) = \frac{1}{2}

cos (θ) = \frac{1}{2} : θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Combine all the solutions

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

(cos (x) - 5) (cos (x) + 1) = 0

sin (t) cos (t) = sin^{2} (t)

cos (x) = \frac{290}{346.7}

tan (x) = \frac{19}{11}

cot (x) = cot (3 x - 5 0^{\circ}), 0 < x < 18 0^{\circ}

What is the general solution for 1-cos(θ)=cos(θ) ?
The general solution for 1-cos(θ)=cos(θ) is θ= pi/3+2pin,θ=(5pi)/3+2pin