What is the general solution for sin(x)=-cos(x),-2pi<= x<= 2pi ?

The general solution for sin(x)=-cos(x),-2pi<= x<= 2pi is x=(3pi)/4 ,x=(7pi)/4 ,x=-pi/4 ,x=-(5pi)/4

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sin(x)=-cos(x),-2pi<= x<= 2pi

sin (x) = - cos (x), - 2 π \leq x \leq 2 π

x = \frac{3 π}{4}, x = \frac{7 π}{4}, x = - \frac{π}{4}, x = - \frac{5 π}{4}

Solution steps

sin (x) = - cos (x), - 2 π \leq x \leq 2 π

Rewrite using trig identities

tan (x) = - 1

General solutions for

tan (x) = - 1

x = \frac{3 π}{4} + πn

Solutions for the range

- 2 π \leq x \leq 2 π

x = \frac{3 π}{4}, x = \frac{7 π}{4}, x = - \frac{π}{4}, x = - \frac{5 π}{4}

sin (θ) = - \frac{7}{8}

sin^{2} (x) sec (x) cot (x) = \frac{3}{2}

x, sin (y) = y cos (2 x)

2 sin (\frac{π}{2} - θ) = sin (- θ)

csc (x) cot (x) + cot (x) = 0

What is the general solution for sin(x)=-cos(x),-2pi<= x<= 2pi ?
The general solution for sin(x)=-cos(x),-2pi<= x<= 2pi is x=(3pi)/4 ,x=(7pi)/4 ,x=-pi/4 ,x=-(5pi)/4