What is the general solution for solvefor θ,cos(θ)=(-1sqrt(2))/2 ?

The general solution for solvefor θ,cos(θ)=(-1sqrt(2))/2 is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin

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solvefor θ,cos(θ)=(-1sqrt(2))/2

solve for

θ, cos (θ) = \frac{- 1 2}{2}

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

Solution steps

cos (θ) = \frac{- 1 \cdot 2}{2}

Simplify

\frac{- 1 \cdot 2}{2} : - \frac{2}{2}

General solutions for

cos (θ) = - \frac{2}{2}

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

cos^{2} (x) - sin (x) + 1 = 0

sin (2 x) = cos (x - 1 5^{\circ})

(1 + cos (4 x)) sin (4 x) = cos^{2} (2 x)

arcsin (\frac{3}{5}) + arccos (x) = π

cos (θ) = \frac{6}{7}

What is the general solution for solvefor θ,cos(θ)=(-1sqrt(2))/2 ?
The general solution for solvefor θ,cos(θ)=(-1sqrt(2))/2 is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin