What is the general solution for sin(2x)=4cos(2x) ?

The general solution for sin(2x)=4cos(2x) is x=(1.32581…)/2+(pin)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(2x)=4cos(2x)

sin (2 x) = 4 cos (2 x)

x = \frac{1.32581 \dots}{2} + \frac{πn}{2}

Solution steps

sin (2 x) = 4 cos (2 x)

Rewrite using trig identities

tan (2 x) = 4

Apply trig inverse properties

2 x = arctan (4) + πn

Solve

2 x = arctan (4) + πn : x = \frac{arctan ( 4 )}{2} + \frac{πn}{2}

x = \frac{arctan ( 4 )}{2} + \frac{πn}{2}

Show solutions in decimal form

x = \frac{1.32581 \dots}{2} + \frac{πn}{2}

- 9 cos^{2} (θ) + 1 = sin (θ)

1 - sin (θ) = sin (θ)

cot (\frac{θ}{3} + \frac{3 π}{4}) = 3

cos (x) = \frac{tan ( x ) + cot ( x )}{csc ( x )}

- tan^{2} (x) - 1 = 0

What is the general solution for sin(2x)=4cos(2x) ?
The general solution for sin(2x)=4cos(2x) is x=(1.32581…)/2+(pin)/2