What is the general solution for 2sin^2(x)=2sin(x)+4 ?

The general solution for 2sin^2(x)=2sin(x)+4 is x=(3pi)/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin^2(x)=2sin(x)+4

2 sin^{2} (x) = 2 sin (x) + 4

x = \frac{3 π}{2} + 2 πn

Solution steps

2 sin^{2} (x) = 2 sin (x) + 4

Solve by substitution

sin (x) = 2, sin (x) = - 1

sin (x) = 2 :

No Solution

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{3 π}{2} + 2 πn

sin (x) cos^{2} (x) = sin (x), 0 \leq x \leq 2 π

2 \cdot cos (4 x) - 1 = 0

2 cos^{2} (θ) - 3 cos (θ) = 2

arctan (0.2 x) = 4 0^{\circ}

sin (x) - sin (2 x) + sin (3 x) = 0

What is the general solution for 2sin^2(x)=2sin(x)+4 ?
The general solution for 2sin^2(x)=2sin(x)+4 is x=(3pi)/2+2pin