What is the general solution for tan(2x-1)=0 ?

The general solution for tan(2x-1)=0 is x=(pin)/2+1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan(2x-1)=0

tan (2 x - 1) = 0

x = \frac{πn}{2} + \frac{1}{2}

Solution steps

tan (2 x - 1) = 0

General solutions for

tan (2 x - 1) = 0

2 x - 1 = 0 + πn

Solve

2 x - 1 = 0 + πn : x = \frac{πn}{2} + \frac{1}{2}

x = \frac{πn}{2} + \frac{1}{2}

cos^{2} (x) = \frac{( 4 k - 3 )}{8}

3 cos^{2} (x) - 8 cos (x) + 4 = 0

sin^{(2)} (x) - sin (x) = 1 - sin^{(2)} (x)

49.55 \cdot 1 - sin^{2} (θ) - 30 sin (θ) = 1.225

cos (2 x) + sin (x) - 1 = 0

What is the general solution for tan(2x-1)=0 ?
The general solution for tan(2x-1)=0 is x=(pin)/2+1/2