What is the general solution for 1/(sqrt(3))=tan(θ) ?

The general solution for 1/(sqrt(3))=tan(θ) is θ= pi/6+pin

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1/(sqrt(3))=tan(θ)

\frac{1}{3} = tan (θ)

θ = \frac{π}{6} + πn

Solution steps

\frac{1}{3} = tan (θ)

Switch sides

tan (θ) = \frac{1}{3}

Simplify

\frac{1}{3} : \frac{3}{3}

General solutions for

tan (θ) = \frac{3}{3}

θ = \frac{π}{6} + πn

(sec^{(2)} (θ)) (cos (θ)) = 2 cos (θ)

sin (x) \cdot tan (x) + 1 = sin (x) + tan (x)

1.33 \cdot sin (5 6^{\circ}) = 1 \cdot sin (x)

cosh (x) = sinh (x)

csc (x) tan (x) = \frac{2 3}{3}

What is the general solution for 1/(sqrt(3))=tan(θ) ?
The general solution for 1/(sqrt(3))=tan(θ) is θ= pi/6+pin