What is the general solution for cosh(x)= 17/15 ?

The general solution for cosh(x)= 17/15 is x=ln(5/3),x=ln(3/5)

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cosh(x)= 17/15

cosh (x) = \frac{17}{15}

x = ln (\frac{5}{3}), x = ln (\frac{3}{5})

Solution steps

cosh (x) = \frac{17}{15}

Rewrite using trig identities

\frac{e ^{x} + e ^{- x}}{2} = \frac{17}{15}

\frac{e ^{x} + e ^{- x}}{2} = \frac{17}{15} : x = ln (\frac{5}{3}), x = ln (\frac{3}{5})

x = ln (\frac{5}{3}), x = ln (\frac{3}{5})

4 cos (x) + 23 = 0

c, 1 = tan (c)

4 cos^{2} (x) + 3 sin^{2} (x) - 4 = - tan^{2} (x)

tan^{2} (x) - 2 = 3 tan (x)

3 cos (x) + sin (x) = 3

What is the general solution for cosh(x)= 17/15 ?
The general solution for cosh(x)= 17/15 is x=ln(5/3),x=ln(3/5)