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人気のある >

4cos^2(x)+3sin^2(x)-4=-tan^2(x)

解

4 cos^{2} (x) + 3 sin^{2} (x) - 4 = - tan^{2} (x)

解

x = 2 πn, x = π + 2 πn

+1

度

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

解答ステップ

4 cos^{2} (x) + 3 sin^{2} (x) - 4 = - tan^{2} (x)

両辺から

- tan^{2} (x)

を引く

4 cos^{2} (x) + 3 sin^{2} (x) - 4 + tan^{2} (x) = 0

三角関数の公式を使用して書き換える

- 4 + tan^{2} (x) + 3 sin^{2} (x) + 4 cos^{2} (x)

ピタゴラスの公式を使用する:

cos^{2} (x) + sin^{2} (x) = 1

cos^{2} (x) = 1 - sin^{2} (x)

= - 4 + tan^{2} (x) + 3 sin^{2} (x) + 4 (1 - sin^{2} (x))

簡素化

- 4 + tan^{2} (x) + 3 sin^{2} (x) + 4 (1 - sin^{2} (x)) : tan^{2} (x) - sin^{2} (x)

- 4 + tan^{2} (x) + 3 sin^{2} (x) + 4 (1 - sin^{2} (x))

拡張

4 (1 - sin^{2} (x)) : 4 - 4 sin^{2} (x)

4 (1 - sin^{2} (x))

分配法則を適用する:

a (b - c) = ab - a c

a = 4, b = 1, c = sin^{2} (x)

= 4 \cdot 1 - 4 sin^{2} (x)

数を乗じる:

4 \cdot 1 = 4

= 4 - 4 sin^{2} (x)

= - 4 + tan^{2} (x) + 3 sin^{2} (x) + 4 - 4 sin^{2} (x)

簡素化

- 4 + tan^{2} (x) + 3 sin^{2} (x) + 4 - 4 sin^{2} (x) : tan^{2} (x) - sin^{2} (x)

- 4 + tan^{2} (x) + 3 sin^{2} (x) + 4 - 4 sin^{2} (x)

条件のようなグループ

= tan^{2} (x) + 3 sin^{2} (x) - 4 sin^{2} (x) - 4 + 4

類似した元を足す:

3 sin^{2} (x) - 4 sin^{2} (x) = - sin^{2} (x)

= tan^{2} (x) - sin^{2} (x) - 4 + 4

- 4 + 4 = 0

= tan^{2} (x) - sin^{2} (x)

= tan^{2} (x) - sin^{2} (x)

= tan^{2} (x) - sin^{2} (x)

- sin^{2} (x) + tan^{2} (x) = 0

因数

- sin^{2} (x) + tan^{2} (x) : (tan (x) + sin (x)) (tan (x) - sin (x))

- sin^{2} (x) + tan^{2} (x)

2乗の差の公式を適用する:

x^{2} - y^{2} = (x + y) (x - y)

tan^{2} (x) - sin^{2} (x) = (tan (x) + sin (x)) (tan (x) - sin (x))

= (tan (x) + sin (x)) (tan (x) - sin (x))

(tan (x) + sin (x)) (tan (x) - sin (x)) = 0

各部分を別個に解く

tan (x) + sin (x) = 0 or tan (x) - sin (x) = 0

tan (x) + sin (x) = 0 : x = 2 πn, x = π + 2 πn

tan (x) + sin (x) = 0

サイン, コサインで表わす

sin (x) + tan (x)

基本的な三角関数の公式を使用する:

tan (x) = \frac{sin ( x )}{cos ( x )}

= sin (x) + \frac{sin ( x )}{cos ( x )}

簡素化

sin (x) + \frac{sin ( x )}{cos ( x )} : \frac{sin ( x ) cos ( x ) + sin ( x )}{cos ( x )}

sin (x) + \frac{sin ( x )}{cos ( x )}

元を分数に変換する:

sin (x) = \frac{sin ( x ) cos ( x )}{cos ( x )}

= \frac{sin ( x ) cos ( x )}{cos ( x )} + \frac{sin ( x )}{cos ( x )}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{sin ( x ) cos ( x ) + sin ( x )}{cos ( x )}

= \frac{sin ( x ) cos ( x ) + sin ( x )}{cos ( x )}

\frac{sin ( x ) + cos ( x ) sin ( x )}{cos ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

sin (x) + cos (x) sin (x) = 0

因数

sin (x) + cos (x) sin (x) : sin (x) (cos (x) + 1)

sin (x) + cos (x) sin (x)

共通項をくくり出す

sin (x)

= sin (x) (1 + cos (x))

sin (x) (cos (x) + 1) = 0

各部分を別個に解く

sin (x) = 0 or cos (x) + 1 = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 0

以下の一般解

sin (x) = 0

sin (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

解く

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

cos (x) + 1 = 0 : x = π + 2 πn

cos (x) + 1 = 0

1

を右側に移動します

cos (x) + 1 = 0

両辺から

1

を引く

cos (x) + 1 - 1 = 0 - 1

簡素化

cos (x) = - 1

cos (x) = - 1

以下の一般解

cos (x) = - 1

cos (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = π + 2 πn

x = π + 2 πn

すべての解を組み合わせる

x = 2 πn, x = π + 2 πn

tan (x) - sin (x) = 0 : x = 2 πn, x = π + 2 πn

tan (x) - sin (x) = 0

サイン, コサインで表わす

- sin (x) + tan (x)

基本的な三角関数の公式を使用する:

tan (x) = \frac{sin ( x )}{cos ( x )}

= - sin (x) + \frac{sin ( x )}{cos ( x )}

簡素化

- sin (x) + \frac{sin ( x )}{cos ( x )} : \frac{- sin ( x ) cos ( x ) + sin ( x )}{cos ( x )}

- sin (x) + \frac{sin ( x )}{cos ( x )}

元を分数に変換する:

sin (x) = \frac{sin ( x ) cos ( x )}{cos ( x )}

= - \frac{sin ( x ) cos ( x )}{cos ( x )} + \frac{sin ( x )}{cos ( x )}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- sin ( x ) cos ( x ) + sin ( x )}{cos ( x )}

= \frac{- sin ( x ) cos ( x ) + sin ( x )}{cos ( x )}

\frac{sin ( x ) - cos ( x ) sin ( x )}{cos ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

sin (x) - cos (x) sin (x) = 0

因数

sin (x) - cos (x) sin (x) : - sin (x) (cos (x) - 1)

sin (x) - cos (x) sin (x)

共通項をくくり出す

- sin (x)

= - sin (x) (- 1 + cos (x))

- sin (x) (cos (x) - 1) = 0

各部分を別個に解く

sin (x) = 0 or cos (x) - 1 = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 0

以下の一般解

sin (x) = 0

sin (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

解く

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

cos (x) - 1 = 0 : x = 2 πn

cos (x) - 1 = 0

1

を右側に移動します

cos (x) - 1 = 0

両辺に

1

を足す

cos (x) - 1 + 1 = 0 + 1

簡素化

cos (x) = 1

cos (x) = 1

以下の一般解

cos (x) = 1

cos (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = 0 + 2 πn

x = 0 + 2 πn

解く

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn

すべての解を組み合わせる

x = 2 πn, x = π + 2 πn

すべての解を組み合わせる

x = 2 πn, x = π + 2 πn

グラフ

人気の例

tan^2(x)-2=3tan(x)

tan^{2} (x) - 2 = 3 tan (x)

sqrt(3)cos(x)+sin(x)=sqrt(3)

3 cos (x) + sin (x) = 3

2 tan^{2} (θ) - 2 = 0

sin^2(x)=2-sin(x)

sin^{2} (x) = 2 - sin (x)

2csc(x)cos(x)=csc(x)

2 csc (x) cos (x) = csc (x)