What is the general solution for 4-4cos(θ)=6 ?

The general solution for 4-4cos(θ)=6 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

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4-4cos(θ)=6

4 - 4 cos (θ) = 6

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solution steps

4 - 4 cos (θ) = 6

Move

4

to the right side

- 4 cos (θ) = 2

Divide both sides by

- 4

cos (θ) = - \frac{1}{2}

General solutions for

cos (θ) = - \frac{1}{2}

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

sin^{2} (θ) - 2 sin (θ) + 1 = 0

cos (4 θ) = - \frac{1}{2}

sin (x) = \frac{2 5}{5}

(2 cos (x) - 1) (sin (x) - 1) = 0

cos (3 2^{\circ}) = sin (5 m) - 12

What is the general solution for 4-4cos(θ)=6 ?
The general solution for 4-4cos(θ)=6 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin