What is the general solution for solvefor 45.6=arcsin((n^1)/(n^2)),n^1 ?

The general solution for solvefor 45.6=arcsin((n^1)/(n^2)),n^1 is n^1=\emptyset n^2

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solvefor 45.6=arcsin((n^1)/(n^2)),n^1

solve for

45.6 = arcsin (\frac{n ^{1}}{n ^{2}}), n^{1}

n^{1} = \emptyset n^{2}

Solution steps

45.6 = arcsin (\frac{n ^{1}}{n ^{2}})

Switch sides

arcsin (\frac{n ^{1}}{n ^{2}}) = 45.6

Subtract

45.6

from both sides

arcsin (\frac{n ^{1}}{n ^{2}}) - 45.6 = 0

Solve by substitution

arcsin (\frac{n ^{1}}{n ^{2}}) = 45.6

Let:

u = \frac{n ^{1}}{n ^{2}}

arcsin (u) - 45.6 = 0

Move

45.6

to the right side

arcsin (u) = 45.6

- \frac{π}{2} \leq arcsin (x) \leq \frac{π}{2}

No Solution

Substitute back

u = \frac{n ^{1}}{n ^{2}}

\frac{n ^{1}}{n ^{2}} = \emptyset : n^{1} = \emptyset n^{2}; n \neq = 0

n^{1} = \emptyset n^{2}

tan (x) = 0.839

sin (\frac{3 ( π - x )}{2}) = 0

sin (x) (2 - sin (x)) = cos^{2} (x)

sin^{2} (θ) = \frac{7}{9}

1 - tan^{2} (θ) = 0

What is the general solution for solvefor 45.6=arcsin((n^1)/(n^2)),n^1 ?
The general solution for solvefor 45.6=arcsin((n^1)/(n^2)),n^1 is n^1=\emptyset n^2