What is the general solution for solvefor x,-sin(2x)=0 ?

The general solution for solvefor x,-sin(2x)=0 is x=pin,x= pi/2+pin

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solvefor x,-sin(2x)=0

solve for

x, - sin (2 x) = 0

x = πn, x = \frac{π}{2} + πn

Solution steps

- sin (2 x) = 0

Divide both sides by

- 1

sin (2 x) = 0

General solutions for

sin (2 x) = 0

2 x = 0 + 2 πn, 2 x = π + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

Solve

2 x = π + 2 πn : x = \frac{π}{2} + πn

x = πn, x = \frac{π}{2} + πn

- 2 sin (x) - 2 sin (x) cos (x) = 0

6 cos^{2} (x) + 5 cos (x) + 1 = 0

tan^{4} (x) + 1 = 4 tan^{2} (x) - 2

tan^{2} (x) = sec (x)

x, sin (x) - sin (2 x) = 0

What is the general solution for solvefor x,-sin(2x)=0 ?
The general solution for solvefor x,-sin(2x)=0 is x=pin,x= pi/2+pin