What is the general solution for -2sin(x)-2sin(x)cos(x)=0 ?

The general solution for -2sin(x)-2sin(x)cos(x)=0 is x=2pin,x=pi+2pin

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-2sin(x)-2sin(x)cos(x)=0

- 2 sin (x) - 2 sin (x) cos (x) = 0

x = 2 πn, x = π + 2 πn

Solution steps

- 2 sin (x) - 2 sin (x) cos (x) = 0

Factor

- 2 sin (x) - 2 sin (x) cos (x) : - 2 sin (x) (cos (x) + 1)

- 2 sin (x) (cos (x) + 1) = 0

Solving each part separately

sin (x) = 0 or cos (x) + 1 = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

cos (x) + 1 = 0 : x = π + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn

6 cos^{2} (x) + 5 cos (x) + 1 = 0

tan^{4} (x) + 1 = 4 tan^{2} (x) - 2

tan^{2} (x) = sec (x)

x, sin (x) - sin (2 x) = 0

sin (θ) = \frac{4}{5}, cos (θ)

What is the general solution for -2sin(x)-2sin(x)cos(x)=0 ?
The general solution for -2sin(x)-2sin(x)cos(x)=0 is x=2pin,x=pi+2pin