What is the general solution for sin(θ/2)-cos(θ/2)=0 ?

The general solution for sin(θ/2)-cos(θ/2)=0 is θ= pi/2+2pin

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sin(θ/2)-cos(θ/2)=0

sin (\frac{θ}{2}) - cos (\frac{θ}{2}) = 0

θ = \frac{π}{2} + 2 πn

Solution steps

sin (\frac{θ}{2}) - cos (\frac{θ}{2}) = 0

Rewrite using trig identities

tan (\frac{θ}{2}) - 1 = 0

Move

1

to the right side

tan (\frac{θ}{2}) = 1

General solutions for

tan (\frac{θ}{2}) = 1

\frac{θ}{2} = \frac{π}{4} + πn

Solve

\frac{θ}{2} = \frac{π}{4} + πn : θ = \frac{π}{2} + 2 πn

θ = \frac{π}{2} + 2 πn

sin (x) = \frac{- 3}{5}

3 cos^{2} (a) + sin^{2} (a) = 2

2 cos (6 x) + 3 = 0

2 = 2 sin (3 θ)

sin (\frac{π}{3} - x) = \frac{1}{2}

What is the general solution for sin(θ/2)-cos(θ/2)=0 ?
The general solution for sin(θ/2)-cos(θ/2)=0 is θ= pi/2+2pin