What is the general solution for cos(3x)=-1,0<= x<= 2pi ?

The general solution for cos(3x)=-1,0<= x<= 2pi is x= pi/3 ,x=pi,x=(5pi)/3

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cos(3x)=-1,0<= x<= 2pi

cos (3 x) = - 1, 0 \leq x \leq 2 π

x = \frac{π}{3}, x = π, x = \frac{5 π}{3}

Solution steps

cos (3 x) = - 1, 0 \leq x \leq 2 π

General solutions for

cos (3 x) = - 1

3 x = π + 2 πn

Solve

3 x = π + 2 πn : x = \frac{π}{3} + \frac{2 πn}{3}

x = \frac{π}{3} + \frac{2 πn}{3}

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{3}, x = π, x = \frac{5 π}{3}

sin (x) = - 3 cos (x)

4 sin^{2} (x) + 2 cos^{2} (x) = 3, 0 \leq x \leq 2 π

sin (x) = - 5

sin (x) = 10

tan (A) = - \frac{3}{91}

What is the general solution for cos(3x)=-1,0<= x<= 2pi ?
The general solution for cos(3x)=-1,0<= x<= 2pi is x= pi/3 ,x=pi,x=(5pi)/3