What is the general solution for sin(pi/2 x)+1=0 ?

The general solution for sin(pi/2 x)+1=0 is x=3+4n

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sin(pi/2 x)+1=0

sin (\frac{π}{2} x) + 1 = 0

x = 3 + 4 n

Solution steps

sin (\frac{π}{2} x) + 1 = 0

Move

1

to the right side

sin (\frac{π}{2} x) = - 1

General solutions for

sin (\frac{π}{2} x) = - 1

\frac{π}{2} x = \frac{3 π}{2} + 2 πn

Solve

\frac{π}{2} x = \frac{3 π}{2} + 2 πn : x = 3 + 4 n

x = 3 + 4 n

3 tan^{2} (x) - tan (x) = 0

sin (2 x) = - \frac{1}{2}, 0 \leq x \leq 2 π

x, 2 sin (x) - 3 = 0

cot (θ + 10 0^{\circ}) = 0

3.8 = 11.8 sin (3.92232 \cdot t)

What is the general solution for sin(pi/2 x)+1=0 ?
The general solution for sin(pi/2 x)+1=0 is x=3+4n