What is the general solution for solvefor x,sin(x+60)=cos(y-37) ?

The general solution for solvefor x,sin(x+60)=cos(y-37) is x=-y+360n+67,x=y+180+360n-187

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,sin(x+60)=cos(y-37)

solve for

x, sin (x + 6 0^{\circ}) = cos (y - 3 7^{\circ})

x = - y + 36 0^{\circ} n + 6 7^{\circ}, x = y + 18 0^{\circ} + 36 0^{\circ} n - 18 7^{\circ}

Solution steps

sin (x + 6 0^{\circ}) = cos (y - 3 7^{\circ})

Rewrite using trig identities

sin (x + \frac{π}{3}) = sin (\frac{π}{2} - (y - \frac{37 π}{180}))

Apply trig inverse properties

x + \frac{π}{3} = \frac{π}{2} - (y - \frac{37 π}{180}) + 2 πn, x + \frac{π}{3} = π - (\frac{π}{2} - (y - \frac{37 π}{180})) + 2 πn

x + 6 0^{\circ} = 9 0^{\circ} - (y - 3 7^{\circ}) + 36 0^{\circ} n : x = - y + 36 0^{\circ} n + 6 7^{\circ}

x + 6 0^{\circ} = 18 0^{\circ} - (9 0^{\circ} - (y - 3 7^{\circ})) + 36 0^{\circ} n : x = y + 18 0^{\circ} + 36 0^{\circ} n - 18 7^{\circ}

x = - y + 36 0^{\circ} n + 6 7^{\circ}, x = y + 18 0^{\circ} + 36 0^{\circ} n - 18 7^{\circ}

y, z = x^{2} sin (x y^{2})

tan (t) = \frac{4}{3}

cos (2 θ) = - sin^{2} (θ)

10 cos (x) = 0

3 sin (x) - 2 = - 2

What is the general solution for solvefor x,sin(x+60)=cos(y-37) ?
The general solution for solvefor x,sin(x+60)=cos(y-37) is x=-y+360n+67,x=y+180+360n-187