What is the general solution for sin(x)=-0.342 ?

The general solution for sin(x)=-0.342 is x=-0.34904…+2pin,x=pi+0.34904…+2pin

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sin(x)=-0.342

sin (x) = - 0.342

x = - 0.34904 \dots + 2 πn, x = π + 0.34904 \dots + 2 πn

Solution steps

sin (x) = - 0.342

Apply trig inverse properties

x = arcsin (- 0.342) + 2 πn, x = π + arcsin (0.342) + 2 πn

Show solutions in decimal form

x = - 0.34904 \dots + 2 πn, x = π + 0.34904 \dots + 2 πn

(cos (x) - 4) (cos (x) + 1) = 0

- 15 + 4 cos (x) = - 15 - 22

tan^{2} (x) sin (x) = tan^{2} (x)

2 sin (θ) = 2, 0 \leq θ < 2 π

2 cos^{2} (t) - 3 cos (t) = - 1

What is the general solution for sin(x)=-0.342 ?
The general solution for sin(x)=-0.342 is x=-0.34904…+2pin,x=pi+0.34904…+2pin