What is the general solution for tan^2(x)sin(x)=tan^2(x) ?

The general solution for tan^2(x)sin(x)=tan^2(x) is x=pin

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tan^2(x)sin(x)=tan^2(x)

tan^{2} (x) sin (x) = tan^{2} (x)

x = πn

Solution steps

tan^{2} (x) sin (x) = tan^{2} (x)

Subtract

tan^{2} (x)

from both sides

tan^{2} (x) sin (x) - tan^{2} (x) = 0

Factor

tan^{2} (x) sin (x) - tan^{2} (x) : tan^{2} (x) (sin (x) - 1)

tan^{2} (x) (sin (x) - 1) = 0

Solving each part separately

tan^{2} (x) = 0 or sin (x) - 1 = 0

tan^{2} (x) = 0 : x = πn

sin (x) - 1 = 0 : x = \frac{π}{2} + 2 πn

Combine all the solutions

x = πn, x = \frac{π}{2} + 2 πn

Since the equation is undefined for:

\frac{π}{2} + 2 πn

x = πn

2 sin (θ) = 2, 0 \leq θ < 2 π

2 cos^{2} (t) - 3 cos (t) = - 1

cos (t) - cos (2 t) = - 0.75

2 cos (A) = - 3

4 sin (x) cos (x) = cos (x)

What is the general solution for tan^2(x)sin(x)=tan^2(x) ?
The general solution for tan^2(x)sin(x)=tan^2(x) is x=pin